NCERT solution Class 12 nuclei

NCERT Solutions

Class 12 Physics

Nuclei

NCERT Questions

Q.1
Q.2
Q.3
Q.4
Q.5
Q.6
Q.7
Q.8
Q.9
Q.10
Q.11
Q.12
Q.13
Q.14
Q.15
Q.16
Q.17
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Q.19
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Q.15

The Q value of a nuclear reaction A + b → C + d is defined by

Q = [m_A + m_b – m_C – m_d] c²

where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic.

(i) ¹₁H + ³₁H → ²₁H + ²₁H

(ii) ¹²₆C + ¹¹₆C → ²⁰₁₀Ne + ⁴₂He

Atomic masses are given to be

m (²₁H) = 2.014102 u , m (³₁H ) = 3.016049 u, m (¹²₆C ) = 12.000000 u

m (²⁰₁₀Ne) = 19.992439 u

Given:

(i)The given nuclear reaction is:

¹₁H + ³₁H → ²₁H + ²₁H

It is given that:

Atomic mass m (¹₁H) = 1.007825 u

Atomic mass m (³₁H) = 3.016049 u

Atomic mass m (²₁H) = 2.014102 u

According to the question, the Q-value of the reaction can be written as:

Q = [m (¹₁H) + (³₁H) -2m (²₁H)] c²

= [1.007825 + 3.016049 - (2 x 2.014102)] c²

Q = (-0.004433) c²

But 1u = 931.5

Therefore Q = - (0.004433 x 931.5)

=-4.0334 MeV

The negative Q-value of the reaction shows that the reaction is endothermic.

(ii)The given nuclear reaction is:

¹²₆C + ¹¹₆C → ²⁰₁₀Ne + ⁴₂He

It is given that:

Atomic mass of m (¹²₆C) = 12.000000 u

Atomic mass of m (²⁰₁₀Ne) = 19.992439 u

Atomic mass of m (₂⁴He) = 4.002603 u

The Q-value of this reaction is given as:

Q = [m (¹²₆C) - (²⁰₁₀Ne) -m (₂⁴He)] c²

= [2 x 12.0 – 19.992439 – 4.002603] c²

= (0.004958 c²) u =0.004958 x 931.5=4.618377 MeV

The positive Q-value of the reaction shows that the reaction is exothermic.

Nuclei Class 12 Physics NCERT Chapter 13 NCERT Solutions

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NCERT solutions of Nuclei Class 12 Physics - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 12 Physics Nuclei NCERT solutions.